AQA A-level PE · Paper 2 · Biomechanical movement · Linear motion: graphs

Read the gradient

Run a 100 m race and watch both exam graphs draw themselves. The gradient of a distance–time graph is speed; the gradient of a velocity–time graph is acceleration. Drag along either graph to freeze any moment.

Time0.00s
Distance0.0m
Velocity0.00m/s
Acceleration0.00m/s²

Model: a smooth velocity curve fitted to typical 10 m split times for each level of athlete. Times start from the athlete's first movement, so reaction time is not included. Velocity is positive towards the finish line. Not any individual athlete's data.

Ready

Teal dots mark where the sprinter was every 1 s: wider gaps = faster.

Athlete:
Graph 1 · gradient = speed

Distance–time

Graph 2 · gradient = acceleration

Velocity–time

Distance (this athlete)Velocity (this athlete)Tangent (gradient at this instant)Other athletes, for comparison
01 · AQA definitions

Learn these word for word

Linear motion
Motion in a straight or curved line, with all body parts moving the same distance in the same direction over the same time.
Scalar
A quantity that has size (magnitude) only. Distance, speed, mass, time.
Vector
A quantity that has both size (magnitude) and direction. Displacement, velocity, acceleration, momentum, force.
Distance
The total length of the path travelled from start to finish. m · scalar
Displacement
The shortest straight-line route from the start point to the finish point. m · vector
Speed
The rate of change of distance. Speed = distance ÷ time taken. m/s · scalar
Velocity
The rate of change of displacement. Velocity = displacement ÷ time taken. m/s · vector
Acceleration
The rate of change of velocity. Acceleration = (final velocity − initial velocity) ÷ time taken. A negative value is a deceleration. m/s² · vector

Worked example. A sprinter goes from 0 m/s to 9 m/s in 1.8 s. Acceleration = (9 − 0) ÷ 1.8 = 5 m/s². Always show the equation, the working and the unit.

02 · Reading the graphs

Gradient and area

Shape of the lineOn a distance–time graphOn a velocity–time graph
Horizontal (flat)Stationary (not moving)Constant velocity (zero acceleration). Flat on the time axis = stationary.
Straight, sloping upConstant speed. Steeper = fasterConstant (uniform) acceleration
Curve getting steeperAcceleratingAcceleration increasing
Curve getting flatterDeceleratingStill accelerating, but by less and less
Sloping down(Displacement–time only) moving back towards the startDecelerating (negative acceleration), while velocity is positive

Gradient = change in the y-axis ÷ change in the x-axis. On a distance–time graph that is metres ÷ seconds = speed. On a velocity–time graph it is (m/s) ÷ s = acceleration. On a curve, the gradient at one instant is the gradient of the tangent at that point, which is what the orange line in the lab shows.

Area under a velocity–time graph = displacement (and the area under a speed–time graph = distance). In the lab, the shaded area always matches the distance readout. You are far more likely to be asked to describe a graph than to calculate an area, but it shows why the two graphs belong together.

03 · Game

Predict the graph

Round 1 of 8Score 0

04 · Exam skill

Plot it yourself

AQA questions often give split times and ask you to plot a graph. Here are a club sprinter's times at every 10 m. Set up the axes, plot each point, then compare your graph with the real curve.

Step 1: set up the axes. Which quantity goes on each axis?

x-axis:
y-axis:

Choose the axes first.

  • Time (the independent variable) goes on the x-axis; distance or velocity on the y-axis.
  • Label both axes with the quantity and the unit: "Distance (m)", "Time (s)".
  • Choose a scale that uses most of the grid and goes up in even steps.
  • Plot accurately (a small cross or dot), then draw a smooth curve or line of best fit. Do not join the dots with straight ruler lines when the shape is a curve.
05 · Scalars and vectors

Distance vs displacement

Event:
Distance0m · scalar
Displacement0m · from the start
Average speed0.00m/s
Average velocity0.00m/s

Quick sort. Scalar or vector?

Score 0 / 0
06 · The 100 m

Describe the velocity–time graph

  1. Start (0 to about 30 m): a steep positive gradient. The sprinter accelerates rapidly from 0 m/s, with the largest acceleration in the first few strides.
  2. Gradient decreases: the sprinter is still accelerating, but by less and less as they approach maximum velocity.
  3. Middle (about 50 to 70 m for an elite sprinter): the graph is close to horizontal. Maximum velocity, roughly constant velocity, acceleration close to zero.
  4. End: a slight negative gradient. The sprinter decelerates a little, usually due to fatigue, even though the finish line is still ahead.

Compare athletes in the lab: the elite athlete reaches a higher maximum velocity, holds it for longer and slows down the least. A less trained athlete reaches maximum velocity earlier and decelerates more.

07 · Exam practice

Try, then check

Question 1 · Define2 marks

Explain the difference between a scalar and a vector quantity. Give one example of each from linear motion.

Show mark scheme
  • Scalar has size/magnitude only, e.g. distance or speed
  • Vector has size/magnitude and direction, e.g. displacement, velocity or acceleration
Question 2 · Calculate2 marks

A sprinter accelerates from 0 m/s to 8.4 m/s in the first 1.4 s of a race. Calculate the sprinter's average acceleration. Show your working.

Show mark scheme
  • Working: (final velocity − initial velocity) ÷ time = (8.4 − 0) ÷ 1.4
  • = 6 m/s² (unit required for the mark)
Question 3 · Calculate4 marks

A 400 m runner completes one lap and finishes on the start line in 50 s. Calculate the runner's distance, displacement, average speed and average velocity.

Show mark scheme
  • Distance = 400 m
  • Displacement = 0 m (finishes where they started)
  • Average speed = 400 ÷ 50 = 8 m/s
  • Average velocity = 0 ÷ 50 = 0 m/s
Question 4 · Interpret3 marks

The velocity–time graph shows a footballer's movement. Describe the motion in sections A, B and C.

Time (s) Velocity (m/s) ABC
Show mark scheme
  • A: positive gradient, so constant/uniform acceleration (velocity increasing from rest)
  • B: horizontal, so constant velocity (zero acceleration)
  • C: negative gradient, so constant/uniform deceleration until stationary
Question 5 · Plot and interpret4 marks

A sprinter's split times are: 10 m 2.0 s, 20 m 3.1 s, 30 m 4.2 s, 40 m 5.2 s, 50 m 6.2 s. Plot a distance–time graph and use it to describe the sprinter's motion.

Show mark scheme
  • Time (s) on the x-axis and distance (m) on the y-axis, both labelled with units
  • Points plotted accurately with a sensible scale, joined by a smooth curve/line of best fit (origin included)
  • The curve gets steeper at first, showing the sprinter is accelerating
  • It then becomes a straight line (equal 10 m splits of 1.0 s), showing a constant speed of about 10 m/s
Question 6 · Sketch and explain5 marks

Sketch and explain a velocity–time graph for an elite sprinter running a 100 m race.

Show mark scheme
  • The line starts at the origin: the sprinter starts at 0 m/s
  • Steep positive gradient at the start: rapid acceleration out of the blocks
  • Gradient decreases as the sprinter approaches maximum velocity (still accelerating, but less)
  • Near-horizontal section in the middle/later part of the race: maximum (roughly constant) velocity, close to zero acceleration
  • Slight negative gradient near the finish: deceleration due to fatigue
  • (Axes must be labelled velocity (m/s) and time (s) for any marks to be credited. Max 5.)